0=-49t^2-98t+735

Solution for 0=-49t^2-98t+735 equation:

0=-49t^2-98t+735

We move all terms to the left:

0-(-49t^2-98t+735)=0

We add all the numbers together, and all the variables

-(-49t^2-98t+735)=0

We get rid of parentheses

49t^2+98t-735=0

a = 49; b = 98; c = -735;
Δ = b2-4ac
Δ = 982-4·49·(-735)
Δ = 153664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{153664}=392$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-392}{2*49}=\frac{-490}{98}
=-5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+392}{2*49}=\frac{294}{98}
=3
$